جایگزین کردن چند کاراکتر مختلف به طور همزمان در پایتون

# Python3 code to demonstrate working of
# Replace Different characters in String at Once
# using join() + generator expression

# initializing string
test_str = 'backendbaz is best'

# printing original String
print("The original string is : " + str(test_str))

# initializing mapping dictionary
map_dict = {'e': '1', 'b': '6', 'i': '4'}

# generator expression to construct vals
# join to get string
res = ''.join(
	idx if idx not in map_dict else map_dict[idx] for idx in test_str)

# printing result
print("The converted string : " + str(res))
# Python3 code to demonstrate working of
# Replace Different characters in String at Once
# using join() + generator expression

# initializing string
test_str = 'backendbaz is best'

# printing original String
print("The original string is : " + str(test_str))

# initializing mapping dictionary
map_dict = {'e': '1', 'b': '6', 'i': '4'}

# generator expression to construct vals
# join to get string
res = ''.join(
	idx if idx not in map_dict else map_dict[idx] for idx in test_str)

# printing result
print("The converted string : " + str(res))
اجرای کد

# Python3 code to demonstrate working of
# Replace Different characters in String at Once
# using regex + lambda
import re

# initializing string
test_str = 'backendbaz is best'

# printing original String
print("The original string is : " + str(test_str))

# initializing mapping dictionary
map_dict = {'e':'1', 'b':'6', 'i':'4'}

# using lambda and regex functions to achieve task
res = re.compile("|".join(map_dict.keys())).sub(lambda ele: map_dict[re.escape(ele.group(0))], test_str)

# printing result
print("The converted string : " + str(res))
# Python3 code to demonstrate working of
# Replace Different characters in String at Once
# using regex + lambda
import re

# initializing string
test_str = 'backendbaz is best'

# printing original String
print("The original string is : " + str(test_str))

# initializing mapping dictionary
map_dict = {'e':'1', 'b':'6', 'i':'4'}

# using lambda and regex functions to achieve task
res = re.compile("|".join(map_dict.keys())).sub(lambda ele: map_dict[re.escape(ele.group(0))], test_str)

# printing result
print("The converted string : " + str(res))
اجرای کد

# Python3 code to demonstrate working of
# Replace Different characters in String at Once

# initializing string
test_str = 'backendbaz is best'

# printing original String
print("The original string is : " + str(test_str))

# initializing mapping dictionary
map_dict = {'e': '1', 'b': '6', 'i': '4'}
for i in test_str:
	if i in map_dict.keys():
		test_str=test_str.replace(i,map_dict[i])

# printing result
print("The converted string : " + str(test_str))
# Python3 code to demonstrate working of
# Replace Different characters in String at Once

# initializing string
test_str = 'backendbaz is best'

# printing original String
print("The original string is : " + str(test_str))

# initializing mapping dictionary
map_dict = {'e': '1', 'b': '6', 'i': '4'}
for i in test_str:
	if i in map_dict.keys():
		test_str=test_str.replace(i,map_dict[i])

# printing result
print("The converted string : " + str(test_str))
اجرای کد